Hackerrank – Problem Statement
A description of the problem can be found on Hackerrank.
Solution
- function
fis an applied algebraic expression toxas in problem description - function
areais area of the cycle ($$\Pi r^2$$) with center0and radius value offunction(x) - function
summationis applied once for functionfand one for functionarea
I created solution in:
All solutions are also available on my GitHub.
Scala
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def f(coefficients: List[Int], powers:List[Int], x: Double): Double = { coefficients.indices.map(i => coefficients(i) * Math.pow(x, powers(i))).sum } def area(coefficients: List[Int], powers: List[Int], x: Double): Double = { scala.math.Pi * scala.math.pow(f(coefficients, powers, x), 2) } def summation(func: (List[Int], List[Int], Double) => Double, upperLimit: Int, lowerLimit: Int, coefficients: List[Int], powers: List[Int]): Double = { val range = lowerLimit.toDouble to upperLimit.toDouble by 0.001 range.map(func(coefficients, powers, _)).sum * 0.001 } |